Ideal Gas Law Calculator
🌬️ Ideal Gas Law Calculator — Understand Gas Behavior Quickly & Accurately
The Ideal Gas Law Calculator is a powerful scientific tool that helps students, chemists, and engineers calculate the relationship between pressure, volume, temperature, and moles of a gas. Whether you’re studying chemistry, performing lab calculations, or working on thermodynamics, this calculator makes complex gas equations simple and fast.
🧠 What Is the Ideal Gas Law?
The Ideal Gas Law describes how gases behave under different conditions of temperature, pressure, and volume.
It is expressed using the famous equation: PV=nRTPV = nRTPV=nRT
Where:
- P = Pressure
- V = Volume
- n = Number of moles
- R = Gas constant
- T = Temperature (in Kelvin)
This formula assumes the gas behaves “ideally,” meaning gas molecules do not interact and occupy negligible space — a useful approximation for many real-world scenarios.
⚙️ How Does the Ideal Gas Law Calculator Work?
Our calculator helps you solve for any one variable in the equation by entering the other three.
You can calculate:
- Pressure (P)
- Volume (V)
- Moles (n)
- Temperature (T)
Gas Constant Value:
R=0.0821 L⋅atm⋅K−1⋅mol−1R = 0.0821 \, L \cdot atm \cdot K^{-1} \cdot mol^{-1}R=0.0821L⋅atm⋅K−1⋅mol−1
Example Inputs:
- Enter temperature in Kelvin
- Enter pressure in atm, Pa, or bar
- Enter volume in liters
- Enter moles of gas
Once you submit the values, the calculator automatically rearranges the Ideal Gas Law equation to compute the missing variable.
🧩 Applications of the Ideal Gas Law
The Ideal Gas Law is widely used in:
- 🔬 Chemistry labs for gas collection & reaction calculations
- 🌡️ Thermodynamics in physics and engineering
- 🏭 Industrial processes involving gas compression or expansion
- 🚀 Aerospace engineering to model atmospheric behavior
- 🎓 Education for solving chemistry and physics problems
It’s one of the most essential equations in gas behavior studies.
📊 Example Calculation
Let’s calculate the volume of a gas sample.
Given:
- Pressure (P) = 2 atm
- Temperature (T) = 300 K
- Amount of gas (n) = 0.5 mol
- Gas constant (R) = 0.0821
Apply the formula: V=nRTPV = \frac{nRT}{P}V=PnRT V=0.5×0.0821×3002V = \frac{0.5 \times 0.0821 \times 300}{2}V=20.5×0.0821×300 V=6.1575 LV = 6.1575 \text{ L}V=6.1575 L
✅ Final Volume = 6.16 liters
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